1+(2/(3t-2))=(8/(3t-2)^2)

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Solution for 1+(2/(3t-2))=(8/(3t-2)^2) equation:


D( t )

3*t-2 = 0

(3*t-2)^2 = 0

3*t-2 = 0

3*t-2 = 0

3*t-2 = 0 // + 2

3*t = 2 // : 3

t = 2/3

(3*t-2)^2 = 0

(3*t-2)^2 = 0

3*t-2 = 0 // + 2

3*t = 2 // : 3

t = 2/3

t in (-oo:2/3) U (2/3:+oo)

2/(3*t-2)+1 = 8/((3*t-2)^2) // - 8/((3*t-2)^2)

2/(3*t-2)-(8/((3*t-2)^2))+1 = 0

2/(3*t-2)-8*(3*t-2)^-2+1 = 0

2/(3*t-2)-8/((3*t-2)^2)+1 = 0

(2*(3*t-2))/((3*t-2)^2)-8/((3*t-2)^2)+(1*(3*t-2)^2)/((3*t-2)^2) = 0

2*(3*t-2)+1*(3*t-2)^2-8 = 0

9*t^2+6*t-12*t-12+4 = 0

9*t^2-6*t-8 = 0

9*t^2-6*t-8 = 0

9*t^2-6*t-8 = 0

DELTA = (-6)^2-(-8*4*9)

DELTA = 324

DELTA > 0

t = (324^(1/2)+6)/(2*9) or t = (6-324^(1/2))/(2*9)

t = 4/3 or t = -2/3

(t+2/3)*(t-4/3) = 0

((t+2/3)*(t-4/3))/((3*t-2)^2) = 0

((t+2/3)*(t-4/3))/((3*t-2)^2) = 0 // * (3*t-2)^2

(t+2/3)*(t-4/3) = 0

( t+2/3 )

t+2/3 = 0 // - 2/3

t = -2/3

( t-4/3 )

t-4/3 = 0 // + 4/3

t = 4/3

t in { -2/3, 4/3 }

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